Question

URGENT!!DAU COROANA SI TOT CE MAI ESTE NEVOIE​

Answer 1

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0

Explicație pas cu pas:

$\sqrt{21 - 12 \sqrt{3} } - \sqrt{52 - 30 \sqrt{3} } - \sqrt{7 - 4 \sqrt{3} } = \sqrt{12 - 2 \cdot 6 \sqrt{3} + 9} - \sqrt{27 - 2 \cdot 15 \sqrt{3} + 25} - \sqrt{4 - 2 \cdot 2 \sqrt{3} + 3} = \sqrt{ {(2 \sqrt{3} )}^{2} - 2 \cdot 2 \sqrt{3} \cdot 3 + {3}^{2} } - \sqrt{ {(3 \sqrt{3} )}^{2} - 2 \cdot 3 \sqrt{3} \cdot 5 + {5}^{2} } - \sqrt{ {2}^{2} - 2 \cdot 2 \sqrt{3} + {( \sqrt{3} )}^{2} } = \sqrt{ {(2 \sqrt{3} - 3)}^{2} } - \sqrt{ {(3 \sqrt{3} - 5)}^{2} } - \sqrt{ {(2 - \sqrt{3} )}^{2} } = |2 \sqrt{3} - 3| - |3 \sqrt{3} - 5| - |2 - \sqrt{3} | = 2 \sqrt{3} - 3 - (3 \sqrt{3} - 5) - (2 - \sqrt{3}) = 2 \sqrt{3} - 3 - 3 \sqrt{3} + 5 - 2 + \sqrt{3} = \bf 0$