Question

Urgent descompuneti in factori

Answer 1

[3(4x+1) - 4(2x+3)] [3(4x+1) + 4(2x+3)]=

(12x+3-8x-12)(12x+3+8x+12)=

(4x-9)(20x+15)=

5(4x-9)(4x+3)

Answer 2

Răspuns

9·(4x + 1)² - 16·(2x + 3)² =

= [3·(4x + 1) - 4·(2x + 3)]·[3·(4x + 1) + 4·(2x + 3)]

= (12x + 3 - 8x - 12)·(12x + 3 + 8x + 12)

=  (4x - 9)·(20x + 15)

= (4x-9)·5·(4x+3)

= 5·(4x-9)·(4x+3)

Explicație pas cu pas:

Am folosit

a² - b² = (a - b)·(a + b)