Question

URGENT EX 11 VA ROG MULT. DAR SA IMI EXPLICATI

Answer 1

n1    Cx(H2x+2)
n2    C(x+1)H(2x+4)          n1/n2 = x/(x+1)    n1/(n1+n2) = x/(2x+1)
[12xn1 + 12(x+1)n2]·100 /[n1·M + n2·(M + 14)] =82,41
(xn1 + xn2 + n2)·1200/[n1(14x + 2) + n2(14x + 16)] = 82,41
1200(xn1 + xn2 + n2) = 82,41·2(7xn1 + n1 + 7xn2 + 8n2)
600[n1(2x+1) + (x+1)/xn1] = 82,41[7n1(2x +1)+ n1(2x+1)/x + 7n1(x+1)/x]
600n1[2x+1+ (x+1)/x] = 82,41n1[7(2x + 1) +(2x +1)/x +7(x+1)/x]
7,28·(2x² + 2x +1)/x = [7(2x +1) + (9x + 8)/x]
7,28(2x²+2x+1)/x = (14x² +16x + 8)/x
14,56x² + 14,56x + 7,28 = 14x² + 16x + 8     0,56x² - 1,44x - 0,72 = 0
7x² - 18x - 9 = 0    x = (9+12)/7 = 3
C3H8; C4H10