Question

urgent!!!! exercitiul 1 de la subiectul 3

Answer 1

a)
AB=1
BC=1,2
DN=NC=1/2=0,5
Afereastra=AB×AD +π×DN²/2=1×1,2 +0,5²×π/2=1,2+0,125π m²

b)ACMDP =0,25+0,6=0,85 m²
Atriunghi DPC=1×0,5/2=0,25
Atriunghi DMC=1×1,2/2=0,6

c)
lungime profil
AB+CB+CD+AD+L(arc DPC)+NM=
=1+1,2+1+1,2+2×0,5π/2+1,2=
=5,6+0,5π=5,6+0,5π=5,6+1,57=7,17 m <7,2 m 
rezulta ca 7,2 m sunt suficienti