Question

URGENT
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Answer 1

Răspuns

1,a)x-->0, x<0 Ls=limf(x)=lim (x+2)=0+2=2

x-->0   x>0 Ld=limf(x)=lim(e^x+1)=e^0+1=1+1=2

f(0)=e^0+1=2

Ls=Ld=f(2)=2

Functia   e    continua     in   0 deci    pe    R

b)x-->∞ lim f(x)=lim(e^x+1)=e^∞+1=∞

c)f²(x)-f(x)=0

f(x)*[f(x)-1]=0=>

f(x)=0

(x+2)=0=>x=-2

e^x+1=0 nu    admite    solutii

f(x)-1=0

x+2-1=0

x=-1

ecuatia e^x+1-1=0 =>e^x=0   nu     admite    solutii

Ex2

a)f(1)-f(e)=(1-ln1)/(1+ln1)-(e-lne)/(e+lne)==(1-0)/(1+0)+(e+1)/(e-1)=

1+(e-1)/(e-1)

b)y=mx+n   ecuatia    asimptotei

x→1 x>1lim f(x)=lim(x-lnx)/(x+lnx)=(1-ln1)/(1+ln1)=(1-0)/(1+0)=1

E

Explicație pas cu pas: