Question

Urgent......lungimea tuburilor este 1 m inloc de 2.8

Answer 1

l₁=n₁λ₁/2

l₂=(2n₂+1)λ₂/4

λ₁=c/υ₁=>υ₁=c/λ₁=cn₁/2l₁

υ₂=c/λ₂=c(2n₂+1)/4l₂

υ₁=υ₂=>2l₁/n₁=4l₂/(2n₂+1)=>l₂=(2n₂+1)l₁/2n₁=(2*2+1)*1/2*2=5/4=1,25 m

l₁=λ₁/2=c/2υ₁=>υ₁=c/2l₁=340/2*1=170 Hz

l₂=λ₂/4=c/4υ₂=>υ₂=c/4l₂=340/4*1,25=340/5=68 Hz