Question

Urgent!Ofer 100 de puncte

Answer 1

Explicație pas cu pas:

a)

$= {( \sqrt{3} + x)}^{2}$

b)

$= {( \sqrt{5} )}^{2} + 2 \cdot \sqrt{5} \cdot \sqrt{3}x + {( \sqrt{3}x)}^{2} = {( \sqrt{5} + \sqrt{3}x)}^{2}$

c)

$= {( \sqrt{2} )}^{2} - 2 \cdot \sqrt{2} \cdot x + {x}^{2} = {( \sqrt{2} - x)}^{2}$

d)

$= {x}^{2} + 2 \cdot x \cdot \sqrt{2} + {( \sqrt{2} )}^{2} = {(x + \sqrt{2} )}^{2}$

e)

$= {( \sqrt{5} )}^{2} - 2 \cdot \sqrt{5} \cdot \sqrt{3}x + {( \sqrt{3}x)}^{2} = {( \sqrt{5} - \sqrt{3}x)}^{2}$

f)

$= {( \sqrt{2}x)}^{2} + 2 \cdot \sqrt{2}x \cdot \sqrt{3} + {( \sqrt{3} )}^{2} = {( \sqrt{2}x + \sqrt{3} )}^{2}$

g)

$= {( \sqrt{7} )}^{2} - 2 \cdot \sqrt{7} \cdot x + {x}^{2} = {( \sqrt{7} - x}^{2}$

h)

$= {(2 \sqrt{5} )}^{2} - 2 \cdot 2 \sqrt{5}z + {z}^{2} = {(2 \sqrt{5} - z)}^{2}$

i)

$= {(2 \sqrt{5}z)}^{2} + 2 \cdot 2 \sqrt{5}z + 1 = {(2 \sqrt{5}z + 1)}^{2}$