Question

URGENT! prin reactia 2,8g metal divalent cu sokutie HCL 36,3% se formeaza 0,05 moli H2 a)masa atomica a nemetalului b)sa se calc cant. solutie acid clorhidric 36,5% consumat

Answer 1

E masa atomica a metalului! Si solutia de HCl e de conc 36,5%
M + 2 HCl = MCl2 + H2
A(M)......................   1 mol H2
2,8 g M...........................0,5 moli H2
A(M) = 56   M = Fe (din sist per)
Fe + 2 HCl = FeCl2 + H2
M(HCl) = A(H)+A(Cl) =1+35,5=36,5
56g Fe..................2*36,5g HCl
2,8 g Fe............................x
x= 3,65 g HCl = md
c/100 = md/ms
ms=100*md/c=100*3,65/36,5=10 g solutie