Question

Urgent!!!!!!!! Sa se rezolve inecuatiile :
a) $\frac{x-3}{x+1} \geq \frac{2x-5}{x+2}$
b)$\frac{x-3}{x-4} \ \textgreater \ \frac{ x^{2} -5x+6}{x-2}$
c)$\frac{ 5x^{2}+7x-3 }{3 x^{2} +x-2} \leq 3$

Answer 1

a)[(x-3)(x+2)-(x+1)(2x-5)]/(x+1)(x+2)≥0⇔(x^2-x-6-2x^2+3x+5)/(x+1)(x+2)≥0⇔
(-x^2+2x-1)/(x+1)(x+2)≥0⇔(x^2-2x+1)/(x+1)(x+2)≤0⇔(x-1)^2*/(x+1)(x+2)≤0
⇔(x+1)(x+2)<0 si x=1
x∈(-2;1)∨{1}