Question

Urgent.....va implor

Answer 1

Forta de interactiune F=G*m₁*m₂/r² (F=0.146mN=146*10⁻⁶N)

unde G-constanta gravitationala G=6.67*10⁻¹¹ N(m/kg)²
m₁ si m₂ -masele celor doua sfere m₁=m₂=m
r-distanta dintre ele, care va fi egala cu suma razelor (R₁=R₂=R)  r=2xR = 2*26*10⁻² = 52*10⁻²m     (26cm=26*10⁻²m)

Deci F=G*m²/r², de unde scoatem masa

m=√(F*r²/G)=√(146×10⁻⁶×52²×10⁻⁴/(6.67*10⁻¹¹))=769.337 kg
Densitatea ρ=m/V   
V=4*π*r³/3= 73,622×10⁻³ m³

ρ=m/V=769.337/(73,622×10⁻³)=10.449×10³ kg/m³ 
Ceea ce e echivalent cu densitatea unui argint.

Answer 2

F = k (m1xm2) / r²

m² = Fxr²/k = 146 x 10⁻⁶ N x (0,26m+0,26m)² / 6,67 x 10⁻¹¹ Nm²/kg  =5,918 x10⁵ 
m = 769,33 kg

d = m / v 
v = 4/3 π R³ = 4/3 π x 0,26³ = 0,073 m³
d = 769,33/ 0,073 = 10 449 kg/m³   === argint