Question

Urgent, va rog! Am nevoie de rezolvare macar la cateva :)

Answer 1

$\it 5)\ \dfrac{a_{k-1}+a_k}{a_k+a_{k+1}} = \dfrac{a_{k-1}+a_k }{a_{k-1}\cdot q+a_k\cdot q} = \dfrac{a_{k-1}+a_k }{(a_{k-1}+a_k)\cdot q} = \dfrac{1}{q}$

Suma din enunț devine :

1/q +1/q +1/q + ... + 1/q  (2013 termeni)

S= 2013 · (1/q) =2013·(1/2013) =1