Question

URGENT VA ROG! DAU COROANA!!!​

Answer 1

${2}^{35} = {2}^{7 \times 5} = ({2}^{7} ) {}^{5} = {128}^{5}$

${5}^{15} = {5}^{3 \times 5} = ( {5}^{3} ) {}^{5} = {125}^{5}$

${11}^{10} = {11}^{2 \times 5} = ( {11}^{2} ) {}^{5} = {121}^{5}$

${121}^{5} < {125}^{5} < {128}^{5} = >$

$= > {11}^{10} < {5}^{15} < {2}^{35}$