Question

urgent va rog!!! dau coroana ​

Answer 1

Răspuns:

2×36,5g...........................2g

Zn + 2 HCl => ZnCl2 + H2

13g...................................xg

MH2=2×1=2g/mol

MHCl=1+35,5=36,5g/mol.

x=13×2/2×36,5=calculează

Answer 2

Răspuns:

0,4g H₂ (0,2 mol H₂)

Explicație:

$\rm M_{H_2}=2A_H=2\dfrac{g}{mol}$

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‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍‍ ‍13g‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍x

2HCl + Zn → ZnCl₂ + H₂↑

‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍65g‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍‍ ‍ ‍ ‍2g

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x = 13 × 2 g / 65 = 0,4 g H₂

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1 mol H₂..........2 g H₂

y mol H₂..........0,4g H₂

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y = 0,4 : 2 = 0,2 mol H₂

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-Mihai