Question

urgent va rog frumos​

Answer 1

Răspuns:

x-1,2=(-b+,-√b^2-4ac)/2a=

x-1,2=(-4+-√16+4×12)/6=

( -4+-√64)/6

( -4+-8)/6

x1=4/6=2/3

x2=-12/6=-2

A-Z=2/3

Answer 2

3x²+4x-4 = 0

delta = 16+12*4 = 16+48 = 64

x1 = (-4+8)/6 = 4/6= 2/3

x2 = (-4-8)/6 = -12/6 = -2

S={-2, 2/3}

S / Z = {2/3}