Question

urgent va rog, mersi.....

Answer 1

a=rad(3-2rad(2))=rad((rad(2)-1)^2)=|rad(2)-1|=rad(2)-1.
b=rad(3+2rad(2))=rad((rad(2)+1)^2)=|rad(2)+1|=rad(2)+1.

Deci b-a=rad(2)+1-(rad(2)-1)=rad(2)+1-rad(2)+1=1+1=2 apartine N.

Media geometrica a numerelor a si b este rad(a*b)=rad((rad(2)-1)*(rad(2)+1))=rad(2-1)=rad(1)=1.