Question

urgent!!!!!!!!!!
va roggggg

Answer 1

Explicație pas cu pas:

$A_{11}^{6} = \dfrac{11!}{(11-6)!} = \dfrac{11!}{5!} = 6 \cdot 7 \cdot 8 \cdot 9 \cdot 10 \cdot 11 = 336 \cdot (9 \cdot 10 \cdot 11)$

$A_{11}^{3} + A_{11}^{4} = \dfrac{11!}{(11-3)!} + \dfrac{11!}{(11-4)!} = \dfrac{11!}{8!} + \dfrac{11!}{7!} = 9 \cdot 10 \cdot 11 + 8 \cdot 9 \cdot 10 \cdot 11 = 9 \cdot 10 \cdot 11 \cdot (1 + 8) = 9 \cdot 9 \cdot 10 \cdot 11$

=>

$336 \cdot (9 \cdot 10 \cdot 11) > 9 \cdot (9 \cdot 10 \cdot 11)$

$\implies A_{11}^{6} > A_{11}^{3} + A_{11}^{4}$