Question

Urgent!!
(x^2+9)(|x+2|-3) mai mic sau egal cu 0

Answer 1

$(x^2+9)(|x+2|-3)\leq 0\\ \\ x^2+9 > 0\quad \forall x\in \mathbb{R}\\ \\ \Rightarrow |x+2|-3 \leq 0 \Rightarrow |x+2|\leq 3 \Rightarrow -3\leq x+2\leq 3 \Rightarrow\\ \\ \Rightarrow -5\leq x\leq 1 \Rightarrow \boxed{x\in [-5,1]}$