Question

URGENTTTTT!!!!!!Dau coroanaaa!!!!!!

Answer 1

$(\sqrt{2})^{-1}*(\sqrt{18}+3)+\frac{6-3\sqrt{2}}{2}=\\ \\=\frac{1}{\sqrt{2}}*(\sqrt{18}+3)+\frac{6-3\sqrt{2}}{2}=\\ \\ =\frac{1}{\sqrt{2}}*\sqrt{18}+\frac{1}{\sqrt{2}}*3+\frac{6-3\sqrt{2}}{2}= \\ \\ =\frac{1}{\sqrt{2}}*3\sqrt{2}+\frac{3}{\sqrt{2}}+\frac{6-3\sqrt{2}}{2}=\\ \\ =3+\frac{3\sqrt{2}}{2}+\frac{6-3\sqrt{2}}{2}=\\ \\ =\frac{6+3\sqrt{2}+6-3\sqrt{2}}{2}=\frac{12}{2}=6.$

/rfd