Question

Urgenttttt va rogggggg mult

Answer 1

   
[tex]\displaystyle\\ a)~~\sqrt{\frac{784}{1225}}=\frac{\sqrt{784}}{\sqrt{1225}}=\frac{28}{35}= \frac{4\times7}{5\times7}=\frac{4}{5}\\\\ b)~~\sqrt[\bf3]{-\frac{125}{64}}=-\sqrt[\bf3]{\frac{125}{64}}=-\frac{\sqrt[\bf3]{125}}{\sqrt[\bf3]{64}}=-\frac{5}{4}\\\\ c)~~\sqrt{\frac{1}{6^4}\cdot\frac{81}{625}}=\sqrt{\frac{1}{6^4}} \cdot \sqrt{\frac{81}{625}}= \frac{\sqrt{1}}{\sqrt{6^4}} \cdot \frac{\sqrt{81}}{\sqrt{625}}=\\\\ = \frac{1}{6^2} \cdot \frac{9}{25}= \frac{9}{36\times 25}= \frac{1}{4\times 25}= \frac{1}{100} [/tex]


[tex]\displaystyle\\ d)~~ \sqrt{ \frac{-216}{343} \cdot \frac{1331}{8}}~~~_\texttt{Nu se poate calcula deoarece sub radical avem numar negativ.}\\\\ e)~~ \sqrt[\bf3]{\sqrt{\frac{729\cdot 81^3}{64^2\cdot 8^4}}}= \sqrt[\bf3]{\frac{\sqrt{729 \cdot 81^3}}{\sqrt{64^2\cdot 8^4}}}= \sqrt[\bf3]{\frac{\sqrt{729}\cdot \sqrt{81^3}}{\sqrt{64^2}\cdot \sqrt{8^4}}}=\\\\ [/tex]

[tex]\displaystyle\\ =\sqrt[\bf3]{\frac{\sqrt{729}\cdot \Big(\sqrt{81}\Big)^3}{\sqrt{64^2}\cdot \sqrt{8^4}}}=\sqrt[\bf3]{\frac{27\cdot 9^3}{64\cdot 8^2}}=\sqrt[\bf3]{\frac{27\cdot 9^3}{64\cdot 64}}=\\\\ =\frac{\sqrt[\bf3]{27}\cdot \sqrt[\bf3]{9^3}}{\sqrt[\bf3]{64}\cdot \sqrt[\bf3]{64}}=\frac{3\cdot 9}{4\cdot 4}=\frac{27}{16}[/tex]