Question

Utilizand proprietatile adunarii,determinati numerele a,b,c,d:
a)$\frac{3}{2} +a=5+ \frac{3}{2}$
b) (3,4+b)+4,7=3,4+(2,17+4,7)
c) 3,294+$\frac{3}{5}$=$\frac{3}{5}$+3,2d4 cu bara de asupra
d)($\frac{4}{7}+ \frac{5}{c}$) +$- \frac{7}{11} = \frac{4}{7} +[ \frac{5}{12} +( -\frac{7}{11} ) ]$

Answer 1

   
[tex]a)~~ \frac{3}{2} +a=5+ \frac{3}{2} ~~ =\ \textgreater \ a = 5+ \frac{3}{2}-\frac{3}{2} = 5 \\ \\ b)~~ (3,4+b)+4,7=3,4+(2,17+4,7) \\ 3,4+b+4,7=3,4+2,17+4,7 \\ b = 3,4+2,17+4,7 -3,4-4,7 = 2,17 \\ \\ c)~~3,294+ \frac{3}{5}= \frac{3}{5}+3,2d4 \\ 3,294 =3,2d4 ~~~ =\ \textgreater \ d = 9 \\ \\ d)~~ ( \frac{4}{7}+ \frac{5}{c}) +(- \frac{7}{11}) = \frac{4}{7} +[ \frac{5}{12} +( -\frac{7}{11} ) ] \\ \frac{4}{7}+ \frac{5}{c} - \frac{7}{11} = \frac{4}{7} + \frac{5}{12} -\frac{7}{11} \\ \frac{5}{c}=\frac{5}{12} ~~~ =\ \textgreater \ c=12[/tex]