Question

utilizind relatiile lui viete rezolvati in Recuatia:x2-5x+6=0
x2+5x-14=0
x2+6x-40=0
x2+8x+7=0

Answer 1

[tex]x^2-5x+6=0 [/tex]

[tex]x1+x2= \frac{-b}{a}= \frac{5}{1}=5 [/tex]

$x1*x2= \frac{6}{1}=6$

[tex]x^2+5x-14=0 [/tex]

[tex]x1+x2= \frac{-b}{a}= \frac{-5}{1}=-5 [/tex]

$x1*x2= \frac{-14}{1}=-14$

$x^2+6x-40=0$

$x1+x2= \frac{-6}{1}=-6$

$x1*x2= \frac{-40}{1}=-40$