Question

Utilizind solutiile AlCl3,NaOH,HCl sau Al2(SO4)3,H2SO4,KOH,obtineti hidroxid de aluminiu si demonstrati amfoteritatea lui.Scrieti ecuatiile reactiilor in forma moleculara si ionica

Answer 1

AlCl3 + 3NaOH⇒ Al(OH)3 + 3NaCl    
Al⁺³+3Cl⁻ +3Na⁺+ 3HO⁻ = Al(OH)3 + 3Na⁺ + 3Cl⁻
Al(OH)3 + NaOH ⇒ Na[Al(OH)4]
Al(OH)3 + Na⁺ + HO⁻ = Na⁺ + [Al(OH)4]⁻
Al(OH)3 + 3HCl ⇒AlCl3 + 3H2O 
Al(OH)3 + 3H⁺ + 3Cl⁻ = Al³⁺ + 3Cl⁻ + 3H2O
Al2(SO4)3 + 6KOH ⇒ 3K2SO4 + 2Al(OH)3 
2Al³⁺ + 3SO4²⁻ + 6K⁺ + 6HO⁻ = 2Al(OH)3 + 6K⁺ + 3SO4²⁻
Al(OH)3 + KOH ⇒ K[Al(OH)4]
Al(OH)3 + K⁺ + HO⁻ = K⁺ + [Al(OH)4]⁻
2Al(OH)3 + 3H2SO4 = Al2(SO4)3 + 6H2O
2Al(OH)3 + 6H⁺ + 3SO4²⁻ = 2Al³⁺ + 3SO4²⁻ + 6H2O