Question

v rog sa ma ajutati
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Answer 1

1. AOB, BOC adiacente

AOC = 148 grade

AOB=?

AOB = AOC + 53

AOB = 148 + 53

AOB = 201

2. ABD, DBC adiacente complementare

Unghiuri complementare, adica suma lor este de 90 grade.

ABD + DBC = 90 grade

BF = bis DBC => DBF = CBF = DBC / 2 (supra 2)

ABF = 82 grade

ABD =?

ABF = ABD + DBF

ABF + FBC = 90

FBC = 90 - 82

FBC = 8 grade

FBC = DBF = 8 grade

DBC = 16 grade

ABD + DBC = 90

ABD = 90 - 16

ABD = 74 grade