Question

v200+v32+v128 cum se calculeaza?

Answer 1

√200+√32+√128.
1. Scoatem factorii de sub radical:
√200= √2*10*10= 10√2
√32= √2*2*2*2*2= 4√2
√128= √2*2*2*2*2*2*2= 8√2
2. Calculam matematic considerand √2 o necunoscuta:
10√2+4√2+8√2= 10a+4a+8a = 22a = 22√2
3. Scriem raspunsul final:
R: 22√2

Answer 2

v(200+32+128)=v*360

daca v inseamna radical:

$\sqrt{200} =10 \sqrt{2}$
$\sqrt{32}= 4\sqrt{2}$
$\sqrt{128}=8 \sqrt{2}$
 deci:
$10 \sqrt{2}+ 4\sqrt{2}+8 \sqrt{x} = 22 \sqrt{2}$