Question

Va doooor ajutor dau corona​

Answer 1

Răspuns:

$k) {3}^{6} \times {3}^{8} \div {3}^{12} + {3}^{2} + {3}^{1} + {3}^{0} = \\ {3}^{14} \div {3}^{12} + 9 + 3 + 1 = \\ {3}^{2} + 9 + 3 + 1 = \\ 9 + 9 + 3 + 1 = \\ 18 + 3 + 1 = \\ 21 + 1 = 22 \\ \\ l) {5}^{5} \times {5}^{8} \div {5}^{10} - {11}^{2} + {11}^{1} - {11}^{0} = \\ {5}^{13} \div {5}^{10} - 121 + 11 - 1 = \\ {5}^{3} - 121 + 11 - 1 = \\ 125 - 121 + 11 - 1 = \\ 4 + 11 - 1 = \\ 15 - 1 = 14 \\ \\ m) {7}^{2} \times ( {7}^{3} \times {7}^{0} \times {7}^{5}) \times {7}^{10} \times {7}^{15} \div {7}^{32} = \\ {7}^{2} \times {7}^{8} \times {7}^{10} \times {7}^{15} \div {7}^{32} = \\ {7}^{10} \times {7}^{10} \times {7}^{15} \div {7}^{32} = \\ {7}^{20} \times {7}^{15} \div {7}^{32} = \\ {7}^{35} \div {7}^{32} = {7}^{3} = 343$

sper că te-am ajutat!!!