Question

va implor sa imi dati rezolvarea completa

Answer 1

(a+b+c):3=20⇒ (a+b+c)=20×3=60

a+b= 40 si (a+b+c)=60⇒ 40 + c = 60⇒ c =60 - 40

⇒ c = 20

(b + c) = 3a⇒ b + 20 = 3a

b + 20 = 3a⇒ b = 3a - 20 si a + b= 40 ⇒ a + 3a -20 = 40⇒ 4a = 60

⇒ a = 15

a + b= 40 ⇒ b = 40 -15 = 25

b = 25

verificare

(a+b+c)=60⇒ 15 + 25 +20 = 60

deci 60 =60

Answer 2

media aritmetica a 3 numere=Ma=(a+b+c)/3=20, a+b=40, inlocuim a+b in Ma

40+c/3=20, aflam valoarea lui c, 40+c=20*3=60, c=60-40=20

b+c=3a, b+20=3a, a=(b+20)/3 stim ca a+b=40, (b+20)/3+b=40, numitor comun 3

b+20+3b=120, 4b=120-20=100, b=100/4=25, a=40-25=15