Question

va provoc sa rezolvati ​

Answer 1

$\bold{1.} \\ V=0,2 \ m^3 \\ p_1=2\cdot 10^5 \ N/m^2 \\ Q=50 \ kJ=50 \ 000 \ J \\ C_V=\frac{5}{2}R \\ R=8,31 \ J/(mol\cdot K} \\ Q=\nu \cdot C_V\cdot \Delta T=\nu\cdot C_V \cdot (T_1-T_2) \\ T_1>T_2; \\ T_1=\frac{p_1V_1}{\nu R}; \ \ \ T_2=\frac{p_2V}{\nu R} \\ \Rightarrow Q=\nu \cdot \frac{5}{2} R \cdot (\frac{p_1V}{\nu R}-\frac{p_2 V}{\nu R})=\frac{5 R \cdot \nu}{2} \cdot \frac{V(p_1-p_2)}{\nu R}=\frac{5V(p_1-p_2)}{2} \\ \Rightarrow 5V(p_1-p_2)=2Q \ \Leftrightarrow \ p_1-p_2=\frac{2Q}{5V}$

$\Rightarrow p_2=p_1-\frac{2Q}{5V}=2 \cdot 10^5 \ N/m^2 -\frac{2 \cdot 50 \ 000 \ J}{5 \cdot 0,2 \ m^3} \\ \Rightarrow \boxed{p_2=10^5 \ N/m^2}};$