Question

Vă rog!!!!!!!!!!!!!!​

Answer 1

c)[3x-6]=7

[3x-6]≤3x-6<(3x-6)+1

=>3x-6=7

3x=13

x=13/3

verificare 13-6=7

d)[x+1/2]=2

[x+1/2]≤x+1/2<x+1/2+1

=>x+1/2=²2

x=3/4

verificare 3/4+1/2=5/2=2 1/2

e)[2x]=x+1/2

2x=x+1/2

x=1/2

verificare 2/2=1/2+1/2