Question

va rog
4 radical 6 + radical 24 - radical 150 + radical 54= ??

8 radical 20 : 4 radical 10 - 15 radical 6 : (-3 radical 3) + 6 radical 14 : (-2 radical 7) =


12 supra radical 14

3 radical 2 supra 5 radical 7

5 supra radical 3 - radical 2​

Answer 1

Răspuns:

4radical din 6

22radical din 2

6radical din 14 supra 7

3 radical din 14 supra 35

5 radical din 3 + 5 radical din 2

(la ultima asa rămâne)

Answer 2

Răspuns:

Vezi rezvolvarile mai jos:

Explicație pas cu pas:

$4\sqrt{6} +\sqrt{24} - \sqrt{50} +\sqrt{54} =\\4\sqrt{6} + 2\sqrt{6} - 5\sqrt{2} + 3\sqrt{6} =\\6\sqrt{6} - 5\sqrt{2} + 3\sqrt{6} =\\9\sqrt{6} -5\sqrt{2}$$8\sqrt{20} : 4\sqrt{10} -15\sqrt{6} : (-3\sqrt{3}) + 6\sqrt{14} : (-2\sqrt{7} )=\\2\sqrt{2} + 5\sqrt{2} - 3\sqrt{2} =\\7\sqrt{2} - 3\sqrt{2} =\\\\5\sqrt{2}$$\frac{12}{\sqrt{14} } \\\\Rationalizam fractia cu \sqrt{14} \\\\\\\frac{12}{\sqrt{14} } = \frac{12\sqrt{14} }{\sqrt{14}  * \sqrt{14} } = \frac{12\sqrt{14} }{14} \\\\\\Simplificam fractia prin 2:\\\\\\ \frac{12\sqrt{14} }{14} = \frac{6\sqrt{14} }{7}$$\frac{3\sqrt{2} }{5\sqrt{7} } \\Rationalizam fractia cu \sqrt{7} \\\\\frac{3\sqrt{2} }{5\sqrt{7} } = \frac{3\sqrt{2} * \sqrt{7} }{5\sqrt{7} *\sqrt{7} } = \frac{3\sqrt{14} }{5 * 7} = \frac{3\sqrt{14} }{35}$$\frac{5}{\sqrt{3} - \sqrt{2} } =\\\\Rationalizam fractia cu \sqrt{3} + \sqrt{2}\\\\ \frac{5}{\sqrt{3} - \sqrt{2} } = \frac{5 * (\sqrt{3} +\sqrt{2})}{(\sqrt{3}-\sqrt{2} )( \sqrt{3} +\sqrt{2} )} = \frac{5 * (\sqrt{3} +\sqrt{2})}{ 3 - 2} = \frac{5 * (\sqrt{3} +\sqrt{2})}{1} = 5 * (\sqrt{3} +\sqrt{2})$