Question

va rog
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Answer 1

Fie1 nr.=a
      2 nr.=b
      3 nr.=c

atunci $\frac{a+b+c}{3}=53$⇒a+b+c=53*3=159;
a=$\frac{1}{3} b$⇒b=3a;
c=a+75;
Atunci a+b+c=a+3a+a+75=159⇔5a+75=159⇔5a=84⇔a=16.8;
b=3a=16.8*3=50.4;
c=a+75=16.8+75=91.8