Question

Vă rog! ! ! ! ! ! !

Answer 1

$x=[(-\frac{3}{4})^{3}*(-\frac{3}{4})^{5}]:[(-\frac{3}{4})^{3}]^{2}=\\ \\ =(-\frac{3}{4})^{8}:(-\frac{3}{4})^{6}=(-\frac{3}{4})^{2}=\frac{9}{16}.\\ \\ \\ ->(2x-\frac{1}{2x})=2*\frac{9}{16}-\frac{1}{2*\frac{9}{16}}=\frac{9}{8}-\frac{1}{\frac{9}{8}}=\frac{9}{8}-\frac{8}{9}=\frac{81-64}{72}=\frac{17}{72}.$

/rfd

Answer 2

$\it x=\left(-\dfrac{3}{4}\right)^{3+5-6}=\left(-\dfrac{3}{4}\right)^2=\dfrac{9}{16}\\\\\\2x=2\cdot\dfrac{9}{16}=\dfrac{9}{8}\\\\\\2x-\dfrac{1}{2x}=\dfrac{^{9)}9}{\ 8}-\dfrac{^{8)}8}{\ 9} =\dfrac{81-64}{72}=\dfrac{17}{72}$