Question

Vă rog!!!!!!!!!!!!!!!!!

Answer 1

Răspuns

Explicație pas cu pas:

$f(-1)=3(-1)^3-2(-1)^2+(-1)+1=-3-2-1+1=-5\\f(-i)=3(-i)^3-2(-i)^2+(-i)+1=3i+2-i+1=2i+3\\f(i+1)=3(i+1)^3-2(i+1)^2+(i+1)+1=\\=3(i^3+3i^2+3i+1)-2(i^2+2i+1)+i+1+1=\\=3(-i-3+3i+1)-2(-1+2i+1)+i+2=\\= 3(2i-2)-4i+i+2=6i-6-3i+2=3i-4$

Observatie: Am folosit faptul ca i³ =-i, i²=-1