Question

Va rog ajutati-ma !!!!!!!!1

0,5* ( 2x - √2)/√3 - 2/3 * (√2-2x)/√3= ( √3/√2(√2x-1) toyul la minus 1+1/5

Answer 1

0,5=5/10=1/2
1/2*(2x-√2)/√3-2/3*(-1)*(2x-√2)/√3=[√3/(2x-√2)]⁻¹+1/5
1/2*(2x-√2)/√3+2/3*(2x-√2)/√3=(2x-√2)/√3+1/5
1/2*(2x-√2)/√3+2/3*(2x-√2)/√3-(2x-√2)/√3=1/5
[(2x-√2)/√3]*(1/2+2/3-1)=1/5
[(2x-√2)/√3]*(3+4-6)/6=1/5
[√3(2x-√2)/3]*1/6=1/5
(2√3x-√6)/18=1/5
5(2√3x-√6)=18
2√3x-√6=18/5
2√3x=√6+18/5
x=√6/2√3+18/10√3
x=√2/2+9/5√3
x=√2/2+9√3/15
x=√2/2+3√3/5