Question

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Answer 1

Răspuns:

Explicație:

560g CaO

a.

r.a.=1Ca : 1O= 1:1

r.m. =ACa : AO= 40:16                      [se simplifica cu 8  ]

                         =5:2

b.

Comp. proc . prin masa moleculara

MCaO=40+ 16=56-------->56g/moli

56g CaO--------40g Ca---------16g O

100 gCaO---------x------------------y

x=100.40 : 56=71,43 % Ca

y=100.16 : 56=28,57% O

c.

nr.moli=n

n=m:M

n=560 g : 56g/moli=10 moli CaO

d.

1mol CaO--------------6,023 .10²³molecule CaO

10 moli---------------------x

x=10 . 6,023.10²³moleculeCaO=60,23.10²³molecule CaO