Question

Va rog,ajutati-ma!!!
a)$\frac{9}{5}(2x+7)-11=16 b)x(8 \frac{1}{2}-5 \frac{3}{4})+ \frac{9}{10}=6 \frac{2}{5}$
c)$\frac{x+1}{3}- \frac{x+4}{2}=- \frac{7}{3}$
Ofer 33 de puncte!!!

Answer 1

lasa recompensele si vezi daca te ajuta
a)
9/5*(2x+7)-11=16 \\ 9*2x/5+9*7/5-11=16 \\ 18x/5+63/5-11=16[/tex]
aduc la acelasi numitor si vom avea
[tex]18x/5+63/5-11*5/5=16*5/5 18x/5+63/5-55/5=80/5 \\ 18x+8/5=80/5 \\ 18x+8=80 \\ 18x=80-8 \\ 18x=72 \\ x=72/18 \\ x=4[/tex]
b) x*(8 intregi si 1/2-5 intregi si 3/4)+9/10=6intregi si 2/5
x*(8*2+1/2-5*4+3/4)+9/10=6*5+2/5
x*(17/2-23/4)+9/10=32/5
x*(17*2/4-23/4)+9/10=32/5
x*(34-23/4(+9/10=32/5
x*11/4+9/10=32/5
11x/4+9/10=32/5 aduc la acelasi numitor in partea stanga
10*11x/40+4*9/40=32/5
110x+36 totul supra 40=32/5
5*(110x+36)=32*40
550x+180=1280
550x=1280-180
550x=1100
x=1100/550
x=2
c) x+1/3 - x+4/2=-7/3 in partea stanga aduc la acelasi numitor
2*(x+1)/6-3*(x+4)/6=-7/3
2x+2/6-(3x+12)/6=-7/3
2x+2-3x-12 totul supra 6=-7/3
-x-10 totul supra 6=-7/3
3*(-x-10)=-7*6
-3x-30=-42
-3x=-42+30
-3x=-12
x=-12/-3
x=4