Question

Va rog, ajutati-ma!

 

Aflati x,y,z,t, stiind ca sunt invers proportionale cu numerele 1/2;1/3;0,4;0,2 si ca suma lor este 5.

Answer 1

0,4= 4/10= 2/5
0,2=2/10=1/5

x,y,z,t ip cu 1/2  1/3  2/5  1/5

x* 1/2=  y*1/3=  z*2/5= t*1/5 =k
x/2 =y/3= 2z/5=t/5=k
x=2k
y=3k
z=5k/2
t=5k

2k+3k+ 5k/2 +5k= 5  aducem la acelasi numitor
4k+6k+ 5k+ 10k=10
25k=10
k=10/25=2/5
x=2 *2/5= 4/5
y=3*2/5= 6/5
z=5* 2/5/2= 2/2=1
t=5*2/5=2