Question

vă rog ajutați mă ,am nevoie urget

Answer 1

[tex]Salut!! \\ \\ \\ \log_2 (x+1) = \log_2 (5) =\ \textgreater \ C.E: x+1 \ \textgreater \ 0 =\ \textgreater \ x \ \textgreater \ -1 =\ \textgreater \ \\Au \:\ baza \:\ 2 \:\ amandoi =\ \textgreater \ x+1=5 =\ \textgreater \ x = 5-1, \boxed{x= 4} \\VERIFICARE: \log_2 (4+1) = \log_2 (5) =\ \textgreater \ \boxed{ \log_2 (5) = \log_2 (5) } \:\ \:\ \\ \\ 3^{3x-1}=9 =\ \textgreater \ 3^{3x-1}=3^2 =\ \textgreater \ \\ =\ \textgreater \ 3x-1 = 2 =\ \textgreater \ 3x=2+1 =\ \textgreater \ 3x=3 =\ \textgreater \ \boxed { x = 1} \\ VERFICARE: 3^{3 \:\ ori \:\ 1 - 1} = 3^2 =\ \textgreater \ \boxed {3^2=3^2}[/tex]