Question

Va rog ajutati-ma!!!!
arcsin 7/25+arccos24/25=arcsin336/625​

Answer 1

Răspuns:

Explicație pas cu pas:

arcsin si arccos  sunt unghiuri

sin(arcsin(x)) = x,  cos(arccos(x))  =x

sin(arccos(x)) = √(1 -x^2),  cos(arcsin(x)) = √(1 -x^2)

Aplicam sinus la ambii termeni:

sin(arcsin336/625​) = 336/625

sin(arcsin 7/25+arccos24/25) =

sin(arcsin 7/25)*cos(arccos24/25) +

 +cos(arcsin 7/25)*sin(arccos24/25) =

= 7/25*24/25 + √(1 -(7/25)^2)*√(1 -(24/25)^2) =

= 168/625 + √(25^2 -7^2)/25*√(25^2 -24^2)/25 =

= 168/625 + 168/625 = 336/625