Question

va rog ajutati-ma cu aceste exercitii

Answer 1

A=-4

B=5+Radical din 2

A<B

$\frac{1}{2+\sqrt{5} } + \frac{1}{2-\sqrt{5} } = \frac{2-\sqrt{5} }{4-5}+ \frac{2+\sqrt{5} }{4-5}  =\frac{2-\sqrt{5} }{-1} +\frac{2+\sqrt{5} }{-1} =-(2-\sqrt{5})+-(2+\sqrt{5})= -2+\sqrt{5}-2-\sqrt{5}=-2-2=-4  (1+\sqrt{2}) ^{2} +2=1+2\sqrt{2} +2+2=5+\sqrt{2}$