Question

Va rog ,ajutați-mă cu cele trei calcule !!!!

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

$\it e)\ \dfrac{\dfrac{^{3)}1}{\ 12}-\dfrac{1}{36}}{(2^3)^5:2^{13}}=\dfrac{\dfrac{1}{3}x}{\dfrac{1}{2}+0,5} \Rightarrow \dfrac{\dfrac{\ 2^{(2}}{36}}{2^{15}:2^{13}}=\dfrac{\dfrac{1}{3}x}{\dfrac{1}{2}+\dfrac{1}{2}} \Rightarrow \dfrac{\dfrac{1}{18}}{4}=\dfrac{\dfrac{1}{3}x}{1} \Rightarrow \\ \\ \\ \Rightarrow\dfrac{1}{18\cdot4}=\dfrac{1}{3}x\ \bigg|_{\cdot3} \Rightarrow x=\dfrac{1}{6\cdot4} \Rightarrow x=\dfrac{1}{24}$