Question

Va rog ajutati-ma, dau 60 de puncte!!

Answer 1

2*3*7/3*49 = 2*7/7*7 = 2/7

2^3*3^2/2^4*3 = 3/2

(3+4)/14 = 7/14 = 1/2

(32-12)/10 = 20/10 = 2

3^12*2^15/3^12*2^13 = 2^2 = 4

49^25/(7^4)^13 = (7^2)^25/7^52 = 7^50/7^52 = 1/7^2 = 1/49

81^10/27^12 = (3^4)^10/(3^3)^12 = 3^40/3^36 = 3^4 = 81

(48-18)/18 = 30/18 = 15/9 = 5/3

(48+8)/8 = 56/8 = 7

Answer 2

$\dfrac{2 \times 3 \times 7}{3 \times 49} ^{ \div 3 \times 7} = \dfrac{2\times 1 \times 1}{1 \times 7} = \dfrac{2}{7}$



$\dfrac{ {2}^{3} \times {3}^{2} }{ {2}^{4} \times 3} ^{ \div {2}^{3} \times 3} = \dfrac{ 1 \times 3 }{2 \times 1} = \dfrac{3}{2}$



$\dfrac{3 + 4}{14} = \dfrac{7}{14} ^{ \div 7} = \dfrac{1}{2}$



$\dfrac{32 - 12}{10}^{ \div 2} = \dfrac{16 - 6}{5} = \dfrac{10}{5} ^{ \div 5} = \dfrac{2}{1} = 2$



$\dfrac{ {3}^{12} \times {2}^{15} }{ {3}^{12} \times {2}^{13} } ^{ \div {3}^{12} \times {2}^{13} } = \dfrac{1 \times {2}^{2} }{1 \times 1} = \dfrac{4}{1} = 4$



$\dfrac{ {49}^{25} }{( {7}^{4}) ^{13} } = \dfrac{ ({ {7}^{2} )}^{25} }{ {7}^{52} } ^{ \div {7}^{49} } = \dfrac{7}{ {7}^{3} } ^{ \div 7} = \dfrac{1}{ {7}^{2} } = \dfrac{1}{49}$



$\dfrac{ {81}^{10} }{ {27}^{12} } = \dfrac{( {3}^{4})^{10} }{( {3}^{3}) ^{12} } = \dfrac{ {3}^{40} }{ {3}^{36} } ^{ \div {3}^{36} } = \dfrac{ {3}^{4} }{1} = \dfrac{81}{1} = 81$



$\dfrac{48 - 18}{18} ^{ \div 6} = \dfrac{8 - 3}{3} = \dfrac{5}{3}$



$\dfrac{48 + 8}{8} ^{ \div 8} = \dfrac{6 + 1}{1} = \dfrac{7}{1} = 7$