Question

va rog ajutați mă dau coroana
doar punctele b,c,d​

Answer 1

Răspuns:

Explicație pas cu pas:

b. Luam mezii cu extremii

6(x+2)=4(x+4)

6x+12=4x+16

2x=4

x=2

c. 6(2x+1)=8(x+3)  |:2

3(2x+1)=4(x+3)

6x+3=4x+12

2x=9

x=$\frac{9}{2}$

d. 65(x+2)=7(2x+1)

65x+130=14x+7

51x=-123

x=$-\frac{123}{51}=-\frac{41}{17}$

Answer 2

Răspuns:

$\frac{x + 2}{x + 4} = \frac{4}{6} \\ (x + 2) \times 6 = (x + 4) \times 4 \\ 6x + 12 = 4x + 16 \\ 6x - 4x = 16 - 12 \\ 2x = 4 \\ x = 4 \div 2 \\ x = 2$

$c) \frac{2x + 1}{8} = \frac{x + 3}{6} \\ (2x + 1) \times 6 = (x + 3) \times 8 \\ 12x + 6 = 8x + 24 \\ 12x - 8x = 24 - 6 \\ 4x = 18 \\ x = \frac{18}{4} = \frac{9}{2}$

$d) \frac{x + 2}{2x + 1} = \frac{7}{65} \\ (x + 2) \times 65 = (2x + 1) \times 7 \\ 65x + 130 = 14x + 7 \\ 65x - 14x = 7 - 130 \\ 51x = - 123 \\ x = - \frac{123}{51}$