Question

Va rog ajutati-ma! E pe luni!

Answer 1

5. a)
2*(1020 : 85+205) : [33*18 -(50*10+23*4)] +1343 : 17 -262=
=2*(12+205) : [594 -(500+92)] +79 -262= 2* 217 : (594-592)+79- 262=
= 434 : 2 +79- 262 = 217+79-262= 296-262= 34
b)
(3*15¹²+2*15¹²) :15¹¹+(3²+3²)³ :(3³+3³):3+1²⁰¹⁵- 2015⁰=
=15¹²*(3+2) : 15¹¹+ (3⁶⁺3⁶): (3³+3³):3+1-1=5¹³: 15¹¹+3⁶*2:3³*2:3=
=15²+3³*: 3=15²+3²=225+9=234

6) a*(a+1)*(a+2)= a*(a²+2a+a+2)= a*(a²+3a+2)
daca a∈N; a≠0
a=1
1*(1²+3*1+2)=1*(1+3+2)=1*6=6 6|6
a=2
2*(2²+3*2+2)=2*(4+6+2)=2*12=24 : 6|24
a=3
3*(3²+3*3+2)=3*(9+9+2)=3*20=60

sau:
1*2*3=6; 6|6
2*3*4=24; 6|24
3*4*5=60; 6|60
etc...