Question

va rog ajutati-ma, este urgent :​

Answer 1

Răspuns:

AB²+AC²=16+12=28=(2√7)²=BC²=>BC ipotenuza =>din reciproca teoremei lui Pitagora=>triunghi dreptunghic

h=AD=(AB·AC)/BC=(4·2√3)/2√7=(4√21)/7cm → teorema inaltimii →h=(c₁c₂)/ip

AB²=BD·BC

16=BD·2√7

BD=(8√7)/7cm

CD=BC=BD=2√7-(8√7)/7=(6√7)/7cm → teorema catetei