Question

VĂ ROG AJUTAȚI-MĂ,ESTE URGENT, DAU COROANĂ!! :(​

Answer 1

a)

$x = \bigg( \dfrac{^{3)} 1}{2} + \dfrac{^{2)} 1}{3} - \dfrac{1}{6}\bigg) \cdot \dfrac{3}{2} =$

$= \dfrac{3 + 2 - 1}{6} \cdot \dfrac{3}{2} = \dfrac{4}{6} \cdot \dfrac{3}{2} = \dfrac{12}{12} = \bf 1$

b)

$y = {16}^{2} : {( {2}^{2} )}^{3} : 2 = {( {2}^{4} )}^{2} : {2}^{2 \cdot 3} : 2 =$

$= {2}^{4 \cdot 2} : {2}^{6} : 2 = {2}^{8} : {2}^{6} : 2^{1} = {2}^{8 - 6 - 1} = \bf 2$

⇒

${(x - y)}^{2022} + {(x - y)}^{2021} = {(1 - 2)}^{2022} + {(1 - 2)}^{2021} =$

$= {( - 1)}^{2022} + {( - 1)}^{2021} = 1 - 1 = \bf 0$

q.e.d.