Question

Va rog ajutati.ma la acest exercitiu dau coroana si 99 puncte. Formula de calcul prescurtat este (a+b)(a-b)=a la puterea a 2 a+ b la puterea a 2 a

Answer 1

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Answer 2

$a)(x + 2)(x - 2) = {x}^{2} - {2}^{2} = {x}^{2} - 4$

$b)(2x - 1)(2x + 1) = {(2x)}^{2} - {1}^{2} = 4 {x}^{2} - 1$

$c)(2x + 3y)(2x - 3y) = {(2x)}^{2} - {(3y)}^{2} = 4 {x}^{2} - 9 {y}^{2}$

$d)(x + 6)(x - 6) = {x}^{2} - {6}^{2} = {x}^{2} - 36$

$e)(3x - 7)(3x + 7) = {(3x)}^{2} - {7}^{2} = 9 {x}^{2} - 49$

$f)(x + 4)(x - 4) = {x}^{2} - {4}^{2} = {x}^{2} - 16$

$g) ( {x}^{2} - 1)( {x}^{2} + 1) = {( {x}^{2}) }^{2} - {1}^{2} = {x}^{4} - 1$

$h)(4x - 3)(4x + 3) = {(4x)}^{2} - {3}^{2} = 16 {x}^{2} - 9$

$i)(5x - 3)(5x + 3) = {(5x)}^{2} - {3}^{2} = 25 {x}^{2} - 9$