Question

Va rog ajutați-mă la aceste doua exerciții
​

Answer 1

Explicație pas cu pas:

1.

a): ?=[180-(37+45)]:2=98:2=49

b) ?=[180-(20+78)]:2=82:2=41

c) COD=35*2=70, COB=180-70=110, ?=110:2=55

d) COD=2*30=60, BOE=180-60-89=31, ?=31:2=15.2

e) AOD=23*2=46, EOB=42*2=84, deci:

COD=23, EOF=42, DOE=180-(46+84)=50

f) COD=19, DOE=31, FOB=180-(38+62)=80

FOD=GOB=80:2=40

g) COD=43, DOB=180-86=94, EOF=FOB=94:2=47

h) AOC=36, DOE=EOF=FOB=(180-72):3=108:3=36

2.

a) 3x+x=180, 4x=180, x=180:4=45; AOC=3*45=135, COB=45

b) x+x+100=180, 2x=180-100=80, x=80:2=40; AOC=40, AOB=100+40=180