Question

Va rog, ajutati-ma la subiectul 4 roman, urgent!!!!!

Answer 1

2*122.5                            3 moli
2KClO3------------- 2KCl + 3O2
490g                                   x

MKClO3= 39*1+35.5*1+16*3=122.5g/mol

Din reactie x=490*3/2*122.5= 6 moli O2
1 mol O2.......................NA =6.022* 10^{23} (nr lui Avogadro)
6 moli O2.......................y
Y= 6*NA= 6.022*10^{23}

Answer 2

2 KClO3 = 2 KCl + 3 O2
M KClO3 = 39+35,5+3*16 = 122,5 g/mol
2*122,5 g KClO3........3 moli O2
490 g KClO3.......................x
x = 6 moli O2
n = nr. molecule/nr. Avogadro
nr. molecule = n*nr. Avogadro = 6*6,022*10^23 = 36,132*10^23 molecule