Question

Va rog ajutati-ma!Mulțumesc anticipat!
Doar punctele: d,g,j,l

Answer 1

$d) {36}^{x} = 0.1(6)$

${36}^{x} = \frac{16 - 1}{90}$

${36}^{x} = \frac{15}{90}$

${36}^{x} = \frac{3}{18}$

${36}^{x} = \frac{1}{6}$

${ ({6}^{2} )}^{x} = {6}^{ - 1}$

${6}^{2x} = {6}^{ - 1}$

$2x = - 1$

$x = - \frac{1}{2}$

$g) {49}^{x} = \frac{1}{343}$

${49}^{x} = {343}^{ - 1}$

${ ({7}^{2} )}^{x} = {( {7}^{3}) }^{ - 1}$

${7}^{2x} = {7}^{ - 3}$

$2x = - 3$

$x = - \frac{3}{2}$

$j) {3}^{4 - |x| } = 1$

${3}^{4 - |x| } = {3}^{0}$

$4 - |x| = 0$

$- |x| = - 4 \: | \times ( - 1)$

$|x| = 4$

$1)x = 4$

$2)x = - 4$

$l) {16}^{x - 1} = 0.25$

${16}^{x - 1} = \frac{25}{100}$

${16}^{x - 1} = \frac{1}{4}$

${4}^{2(x - 1)} = {4}^{ - 1}$

${4}^{2x - 2} = {4}^{ - 1}$

$2x - 2 = - 1$

$2x = - 1 + 2$

$2x = 1$

$x = \frac{1}{2}$