Matematică, întrebare adresată de andreioneataandrei62, 7 ani în urmă

va rog ajutați mă
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Anexe:

Răspunsuri la întrebare

Răspuns de andyilye
2

k)

7 : 4\dfrac{2}{3} = 7 : \dfrac{4 \cdot 3 + 2}{3} = 7 : \dfrac{12 + 2}{3} = 7 : \dfrac{14}{3} = \not 7 \cdot \dfrac{3}{\not 14} = \dfrac{3}{2} = 1\dfrac{1}{2}

l)

4\dfrac{2}{6} : 2\dfrac{1}{6} = \dfrac{4 \cdot 6 + 2}{6} : \dfrac{2 \cdot 6 + 1}{6} = \dfrac{24 + 2}{6} : \dfrac{12 + 1}{6} = \dfrac{26}{6} : \dfrac{13}{6} = \dfrac{26}{\not6} \cdot \dfrac{\not6}{13} = \dfrac{26}{13} = 2

m)

2\dfrac{4}{7} : \dfrac{12^{(2}}{14} = \dfrac{2 \cdot 7 + 4}{7} : \dfrac{6}{7} = \dfrac{14 + 4}{7} \cdot \dfrac{7}{6} = \dfrac{18}{\not7} \cdot \dfrac{\not7}{6} = \dfrac{18}{6} = 3

n)

4\dfrac{1}{5} : \dfrac{3}{25} = \dfrac{4 \cdot 5 + 1}{5} \cdot \dfrac{25}{3} = \dfrac{\not21}{\not5} \cdot \dfrac{\not25}{\not3} = \dfrac{7}{1} \cdot \dfrac{5}{1} = 35

o)

3\dfrac{10}{13} : 2\dfrac{1}{26} = \dfrac{3 \cdot 13 + 10}{13} : \dfrac{2 \cdot 26 + 1}{26} = \dfrac{39 + 10}{13} : \dfrac{52 + 1}{26} = \dfrac{49}{13} : \dfrac{53}{26} = \dfrac{49}{\not13} \cdot \dfrac{\not26}{53} = \dfrac{49}{1} \cdot \dfrac{2}{53} = \dfrac{98}{53} = 1\dfrac{45}{53}

Răspuns de TheFlashseason9
1

Răspuns:

k) 3/2

l) 2

m) 3

n) 35

o) 1274/689

Explicație pas cu pas:

k) 7:4•3+2/3=

=7:12+2/3

=7:14/3

=7/1:14/3

=7/1•3/14

=21/14

=3/2

l) 4•6+2/6:2•6+1/6=

=24+2/6:12+1/6

=26/6:13/6

=26/6•6/13

=156/78

=2

m) 2•7+4/7:12/14=

=14+4/7•14/12

=18/7•14/12

=252/84

=3

n) 4•5+1/5:3/25=

=20+1/5•25/3

=21/5•25/3

=525/15

=35

o) 3•13+10/13:2•26+1/26=

=39+10/13:52+1/26

=49/13:53/26

=49/13•26/53

=1274/689

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